How do you solve this problem: A roofer leans a 20 foot ladder against a house, the base of the ladder is 7 feet from the house, to the nearest tenth of a foot, how tall is the house?
For this problem, consider a triangle. The house forms a right angle with the ground, so the length of the ladder is the hypotenuse. So, 400=49+x^2 which is x=sqrt(351). To the nearest tenth of a foot, the house is 18.7 feet. ChaCha on!
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