How many milliliters of a 48% sulfuric acid solution must be added to 24 milliliters of 12% sulfuric acid solution to produce a 30% sulfuric acid solution?


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Sulfuric Acid 24mL of a 48% sulfuric acid. x 24 x + 2448% 12% 30% * make sure to draw a bucket around the percntages48x + 12(24) = 30(x + 24)48x + 288 = 30x + 72048x - 30x = 720 - 28818x = 432x = 24mL of a 48% sulfuric acid

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