How to find sin(x) if cos(x)=7/8?
Using the Pythagorean theorem, 7sq + xsq =8sq. 49+xsq= 64. xsq= 15, so x is the square root of 15. Therefore sin (x)= sqroot 15 / 8. Thanks for using ChaCha!
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About Pythagorean Theorem
The Pythagorean Theorem states ''In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).''
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