If a train left Shawnee traveling due west at 90 miles per hour, a car left Shawnee at the same time traveling due east at 60 miles per hour, how much time will pass?


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The answer to this problem is - t*90+t*60=405t*(90+60)=405t(150)=405t=405/150t=27/10t=2.7 hours or 2 hrs 42 minutesAre you sure the distance is not 450?IF it were 450 then we havet*(90+60)=450t*150=450t=3 hours ChaCha on!

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