If hydrocarbon gas with an empirical formula CH2 has a density of 1.88 grams per liter at 0 Celsius and 1 atm. What is the possible formula for the hydrocarbon and why?
A hydrocarbon gas with an empirical formula CH2 has a density of 1.88 grams per liter at 0o C and 1.00 atmosphere. Molar mass = d x RT / p = 1.88 x 0.0821x 273 K / 1 = 42.13 g/mol CH2 => molar mass = 14.027 g/mol 42.13 / 14.027 =3. You then multiply by 3 the empirical formula to get C3H6 (propene)
Answered by Laura S. -
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